Monday

March 30, 2015

March 30, 2015

Posted by **Gina** on Tuesday, May 27, 2008 at 7:35pm.

cot(x/4) - cot(x) = [sin(kx)]/[sin(x/4)sin(x)]

PLEASEEEE HELP! ASAP!

- Math -
**???**, Tuesday, May 27, 2008 at 8:54pmThat is a very confusing question, you may want to reword that if you want an answer

- Math -
**Reiny**, Tuesday, May 27, 2008 at 10:19pmthe left side

= cot(x/4) - cot(x)

= [cos(x/4)/sin(x/4)] - cos(x)/sin(x)

= [sin(x)cos(x/4)- cos(x)sin(x/4)]/[sin(x/4)sin(x)]

= sin(x - x/4)/[sin(x/4)sin(x)]

comparing left side with right side, we notice the denominators are the same, so the numerator has to be the same

then sin(x - x/4) = sin (kx)

and x-x/4 = kx

3x/4 = kx

k = 3/4

**Answer this Question**

**Related Questions**

algebra - Can someone please help me do this problem? That would be great! ...

Trigonometry - Please review and tell me if i did something wrong. Find the ...

Math (Trig) - sorry, another I can't figure out Show that (1-cot^2x)/(tan^2x-1)=...

Trigonometry - Hello all, In our math class, we are practicing the trigonometric...

math - use the quotient and reciprocal identities to simplify the given ...

Trigonometry - Proof - Prove that cot x + tan x = csc x * sec x whenever both ...

Precalculus - Show that cot((x+y)/2)=-(sin(x)-sin(y))/(cos(x)-cos(y)) for all ...

verifying trigonometric identities - How do I do these problems? Verify the ...

Calculus - Consider the function f(x)=sin(1/x) Find a sequence of x-values that ...

Math - Which of the following are inverse functions? 1. Arcsin x and sin x 2. ...