Thursday
April 17, 2014

Homework Help: Chemistry

Posted by howie on Tuesday, May 27, 2008 at 4:45pm.

Calculate the percent ionization of cyanic acid, Ka=2.0x10^-4, in a buffer soln that is .50M HCNO and .10M NaCNO.

Answer is .20%.
So,I know that NaCNO-->Na+ + CNO-
so [CNO-]=.10M from ICF chart.
and then HCNO <=>H+ + CNO-
where: [HCNO]= .5
and [CNO-]=.1
With an ice table , i keep on getting x=.001 which means the percent ionization would be 1% instead of .2%

Help!

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