Posted by howie on Tuesday, May 27, 2008 at 4:40pm.
The HH equation won't work for this. Let's call saccharin HS, then the ionization is
HS ==> H^+ + S^-
Ka = (H^+)(S^-)/(HS)
So you know pH, convert that to (H^+). The (S^-) is the same thing. The (HS) = the unionized saccharin, is 0.015 - (H^+). Solve for Ka. You may have a quadratic equation. I didn't examine it closely enough to see.
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