Posted by **howie** on Tuesday, May 27, 2008 at 4:40pm.

Sacchirin is a monoprotic acid. If the pH of a 1.50x10^-2M solution of this acid is 5.53, what is the Ka of saccharin?

(the answer is 5.8x10^-10)

I know we're supposed to use the Henderson Hasselbach equation to solve for the [H+] from pH, but what's next?

Thanks Dr. Bob.

- Chemistry -
**DrBob222**, Tuesday, May 27, 2008 at 10:37pm
The HH equation won't work for this. Let's call saccharin HS, then the ionization is

HS ==> H^+ + S^-

Ka = (H^+)(S^-)/(HS)

So you know pH, convert that to (H^+). The (S^-) is the same thing. The (HS) = the unionized saccharin, is 0.015 - (H^+). Solve for Ka. You may have a quadratic equation. I didn't examine it closely enough to see.

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