calculus
posted by chelsea .
identify the conic section. Write in standard form and graph.
5x^26y^230x12y+9=0

5x^26y^230x12y+9=0
lets complete the square
5(x^2  6x + ___) 6(y^2 + 2y + ___) = 9
5(x^2  6x + 9) 6(y^2 + 2y + 1) = 9 + 45  6
5(x3)^2  6(y+1)^2 = 30
divide both sides by 30
(x3^2 /6  (y+1)^2 /5 = 1
I will leave it up to you to identify the conic and its properties.