Posted by T on .
a plane with an airspeed of 192mi/h is headed on a bearing of 121 degrees. a north wind is blowing (from north to south) at 15.9 mi/h . find the ground speed and the actual bearing of plane.
I will assume you are using the standard 'true north' reference and a clockwise rotation resulting a vector in the fourth quadrant with a magnitude of 192.
draw a vector from the end of the previous vector due south with a magnitude of 15.9
draw in the resultant vector
by cosine law:
R^2 = 192^2 + 15.9^2 - 2(192)(15.9)cos 121º
R will be the ground speed.
Use the Sine Law to find the angle across from the 15.9 side, add that angle to 121 and you have your actual bearing.
math ? -
is it gonna be right traingle or what?
math - IS IT COREECT -
15.9 * 121 *
*))90 (( *