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February 1, 2015

February 1, 2015

Posted by **T** on Saturday, May 24, 2008 at 10:44pm.

- math -
**Reiny**, Sunday, May 25, 2008 at 12:11amI will assume you are using the standard 'true north' reference and a clockwise rotation resulting a vector in the fourth quadrant with a magnitude of 192.

draw a vector from the end of the previous vector due south with a magnitude of 15.9

draw in the resultant vector

by cosine law:

R^2 = 192^2 + 15.9^2 - 2(192)(15.9)cos 121º

R will be the ground speed.

Use the Sine Law to find the angle across from the 15.9 side, add that angle to 121 and you have your actual bearing.

- math ? -
**T ??????????**, Sunday, May 25, 2008 at 5:44pmis it gonna be right traingle or what?

- math - IS IT COREECT -
**T ??????????**, Sunday, May 25, 2008 at 5:54pm*

* *

15.9 * 121 *

* *

*))90 (( *

**************

192

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