Posted by T on Saturday, May 24, 2008 at 10:43pm.
a traingle has an area 48 square cm and its shorter sides have lengths 9cm and 12cm. find the lagest angle of the traingle.

MATH  Reiny, Saturday, May 24, 2008 at 11:51pm
Area of triangle = side1*side2*sin(angle between them)/2
so 48 = 1/2(12)(9)sin ß
sin ß = 48/54
ß = 62.7º or 117.26º
If the angle is 62.7
Using the cosine law I found the side across from the 62.7º to be 11.226 and then using the sine law once more found the angle across from the side of 9 to be 45.44º surely making all three angles acute.
So the largest angle in the triangle must be in the second case, where the angle was 117.7º
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