Posted by **T** on Saturday, May 24, 2008 at 10:41pm.

Two Planes leave an airport at the same time, one flying 300km/h and the other at 420km/h

The angle between their flight paths is 75 degrees after three hours, how fart apart are they?

answer:

so it would be c^2=a^2+b^2-2ab cos C

900^2+1260^2-2(900)(1260)(cos75)

c^2=33542.9

c=183.14km

is it right?

- MATH -
**Reiny**, Sunday, May 25, 2008 at 12:01am
c^2 = 900^2+1260^2-2(900)(1260)(cos75) correct

= 810,000 + 1,587,600 - 587,001.59

= 1,810,598.4 (you had 33542.9)

c = √1,810,598.4

c = 1345.58

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