Wednesday
March 4, 2015

Homework Help: Math

Posted by Tareena-- check my answer please on Saturday, May 24, 2008 at 4:26pm.

The Captain of a freighter 8km fromthe nearer of two unloading docks on the shore finds that the angle between the lines of sight to the docks is 35 degrees. if the docks are 10km apart, how far is the tanker from the farther dock?


My answers :

idont know whis one is right
method # 1:
suppose b= 8, c=10,a=?
a^2+b^2=c^2
a^2=(10)^2-(8)^2=
100-64=36
taking sqaur root of 36
a=6

method #2

A= unknown
B= unknown
C=35 degrees
a=unkown
b=8km
c=10km
using law of sin
sin 35/10=sinB/8
=.45
B=.45 dgrees
then B+C-180=A
.45+35-180=144.5
A=144.5
using law of sin
sin 35/10=sin 144.5/a
=10.12
a=10.12

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