x2-13x+30
That expression can be factored to
(x-10)(x-3)
If you had written the equation,
x2-13x+30 = 0
you could now say what x is, but you didn't.
So that's about as far as I can go wth your question.
i think it islike thisx2-13x+30=x2-10x+3x+30=x(x-10)-3(x-10)=(x-3)(x-10)
5x2+13x+6
To find the solutions to the quadratic equation x^2 - 13x + 30 = 0, you can use the quadratic formula. The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x are given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, a = 1, b = -13, and c = 30. Plugging these values into the quadratic formula, we get:
x = (-(-13) ± √((-13)^2 - 4(1)(30))) / (2(1))
Simplifying further:
x = (13 ± √(169 - 120)) / 2
x = (13 ± √49) / 2
x = (13 ± 7) / 2
Thus, the solutions to the quadratic equation x^2 - 13x + 30 = 0 are:
x = (13 + 7) / 2 = 10
x = (13 - 7) / 2 = 3
Therefore, the equation x^2 - 13x + 30 = 0 has two solutions: x = 3 and x = 10.