Posted by micole on Friday, May 23, 2008 at 2:18pm.
Henderson equations deal with a weak acid or base salt. Here that is Not the case.
the lye neutralized half the acid...so you have started with a volume of .050liter. Moles of acid was .1*.050=.005 moles. You are left .0025 moles acid in a volume of .075 liters (you added 25ml)
pH=-log(.0025/.075)=1.48 check that.
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