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July 22, 2014

July 22, 2014

Posted by **Alex** on Friday, May 23, 2008 at 12:05am.

a) A 4kg bowling ball strikes a stationary pin head-on at a speed of 3m/s. It continues to move in its original direction, but its speed is reduced to 2m/s.

b) A 200g rubber ball falling vertically strikes ground at a speed of 10m/s and bounces vertically upwards, leaving ground at speed of 6m/s.

c) A 4kg bowling ball moving at 2.5m/s strikes a pin in a glancing fashion. It is deflected through an angle of 10degrees. It's speed is reduced to 2m/s.

Can someone please explain how change in momentum can be calculated first of all and then go over the those questions and please explain what you did.

Sorry for the triple-post. Please ignore whichever immature person answers this using my name.

- Physics -
**Anonymous**, Friday, May 23, 2008 at 12:48ammomentum can be found by multiplying mass and velocity together.

a) (4kg)(3m/s)-(4kg)(2m/s)

- Physics -
**bobpursley**, Friday, May 23, 2008 at 5:59amUse the definition of change in momentum, a vector operation.

changeinmomentum= Finalmomentum -initial momentum

= massfinal(velocityfinal)-massinitial(velocityinitial)

= mass (Vf-Vi)

Now remember, you have direction associated with Vf and Vi.

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