Thursday

March 5, 2015

March 5, 2015

Posted by **Alex** on Thursday, May 22, 2008 at 8:09pm.

f(x) = -3x^4/(sqrt(4x-8))

g(x) = ((2x+5)/(6-x^2)^4

g(x) = (8x^3)(4x^2+2x-3)^5

y = [1/(4x+x^2)^3]^3

Thank you so much!

- Calculus -
**Reiny**, Thursday, May 22, 2008 at 10:09pmI will give you the 'first-line' derivatives of the first two questions

a) f'(x) = [(4x-8)^(1/2)(-12x^3) - (-3x^4)(1/2(4x-8)^(-1/2)(4)]/(4x-8)

= ....

b) I see you had a double bracket at the front, but one bracket is not closed.

Did you mean [(2x+5)/(6-x^2)]^4 ?

c) g(x) = (8x^3)(4x^2+2x-3)^5

g'(x) = 5(4x^2+2x-3)^5(8x+2)(8x^3) + 24x^2(4x^2+2x-3)^5

= ....

d) y = [1/(4x+x^2)^3]^3

y = (4x+x^2)^-9

y' = -9(4x + x^2)^-10(4+2x)

= ....

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