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November 29, 2014

November 29, 2014

Posted by **robert** on Thursday, May 22, 2008 at 7:11pm.

- calculus -
**drwls**, Thursday, May 22, 2008 at 7:23pmI suggest you use integration by parts.

Let x^2 dx = du and v = arctan (6x)

u = x^3/3

dv = 6 dx/[1 + (6x)^2]

The integral is uv - Integral of u dv

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