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November 23, 2014

November 23, 2014

Posted by **Anonymous** on Thursday, May 22, 2008 at 10:30am.

g maps points (0,0),(1,0),(0,1) to (6,-2),(6,-1),(5,-2)

So, g(x) = (0 -1) .....(6)

..................(1 0)x + (-2)

f is a reflection through y=x-2

so, f(x) = (0 1) .....(2)

...............(1 0)x + (-2)

So; f o g = g(f(x))

= (0 -1)(0 1) ...(0 -1)(2) .....(6)

...(1 0)(1 0)x + (1 0)(-2) + (-2)

= (-1 0) ....(2) ....(6)

....(0 1)x + (2) + (-2)

= (-1 0) .....(8)

....(0 1)x + (0)

This is really stretching my brain.

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