Monday

September 15, 2014

September 15, 2014

Posted by **Anonymous** on Thursday, May 22, 2008 at 2:07am.

v(t)=25tsin(t^2)

At time=0, you were backed up against the bumper of your car.

How far were you from your car two minutes after you started walking?

Integral (0 to 2) v(t) dt = 20.671

What was your acceleration 1 minute into your walk?

V’(1)=48.052

At what time was your instantaneous velocity as your average velocity over the first minute? (how do I solve this?)

- Calculus -
**drwls**, Thursday, May 22, 2008 at 5:30amYour V'(1) looks OK.

It is 50 cos 1 + 25 sin 1

I didn't check your integral.

Your wording of the last question, with the word "as", doesn't make sense to me. Do you mean to ask

"At what time was your instantaneous velocity equal to your average velocity over the first minute?"

To answer this, set

v(t) = (distance traveled)/t = x(t)/t

Use your x(t) solution to get that.

**Answer this Question**

**Related Questions**

aLGEBRA - Tracy wants to purchase custom-made bumper stickers to advertise her ...

cars - Which one of these statements is true about a "bumper-to-bumper" warranty...

physics - A car is equipped with a bumper that is designed to absorb collisions...

Physics - Jenny and Betty are having a great time at Busch Gardens riding the ...

physics - The force sensor measures the force on the sensor due to the bumper, ...

social studies - hello, my homework page starts out with In 1979, muslim ...

math(check answers) - please check my math!! THANKS SO MUCH 1. Identify the ...

physics - A 5kg mass is sliding at a speed of 7 m/s on horizontal sheet of ...

chemistry - A car bumper is plated with chromium using chromium(III) ions in ...

Algebra II - Suppose that the profit, p, for selling bumper stickers is given by...