Posted by **Anonymous** on Thursday, May 22, 2008 at 1:36am.

Can you check my work and see if I did the problem correctly? Thanks!

A solid with a base formed by intersecting sine and cosine curves and built up with semi-circular cross-sections perpendicular to the x-axis. Find the area of the base and the volume of the solid.

Integral (-2.356 to .785) (sinx-cosx) dx =-2.828

½ pi Integral (-2.356 to .785) (.5(sinx-cosx))^2 dx = 1.234

## Answer this Question

## Related Questions

- Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...
- Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...
- Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...
- Calculus - Hi, I have a calculus question that I just cannot figure out, it is ...
- Calculus - Hi, I have a calculus question that I just cannot figure out, it is ...
- Calculus - The base of a solid in the first quadrant of the xy plane is a right ...
- Calculus - This problem set is ridiculously hard. I know how to find the volume ...
- Calculus - Let f and g be the functions given by f(x)=1+sin(2x) and g(x)=e^(x/2...
- calculus - 1. A solid is constructed so that it has a circular base of radius r ...
- Calculus AP - Let R be the region in the first quadrant bounded by the graph y=3...

More Related Questions