Posted by Anonymous on Thursday, May 22, 2008 at 1:10am.
100-y=Ce^-k
yes agree so y = 100 - C e^-kt
let's call t = 0 at 10 am
so at 10 am
68 = 100 - Ce^0 = 100 -C
so
C = 32
now
y = 100 -32 e^-kt
well, at t = 60 min which is 11 am, y = 87.5
so
87.5 = 100 - 32 e^-60 k
32 e^-60 k = 12.5
e^-60 k = .3906
-60 k = ln .3906 = - .94
k = .0157
so in the end
y = 100 - 32 e^-.0157 t
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