Posted by **Tom** on Thursday, May 22, 2008 at 12:16am.

Sorry for posting so many topics, but I really need help on this stuff. I recently lost my work I did on a seperate sheet from 2 weeks ago, and now I can't seem to find the answer again.

a fair six-sided die is tossed seven times in a row.

A) What is the probability that a "4" comes up exactly four times? (I got 4375/279936)

B) What is the probability that a "4" comes up an even number of times? (I got 2315/4374)

C) What is the probability that a number higher than "4" Comes up exactly four times (I got 280/2187)

Can anyone help me with this. I need to know how I got these answers again.

- Probability. -
**Anonymous**, Thursday, May 22, 2008 at 2:23am
Since a die is tossed seven times, for a), we want 4 comes up four times and a number other 4 three times. So,

(1/6)^4(5/6)^3

I think you can do the rest now.

- Probability. -
**Reiny**, Thursday, May 22, 2008 at 8:19am
not that simple

suppose we call getting a 4 is success (S) and not getting a 4 if failure (F)

one possibilty is SSSSFFF

The probability of that is (1/6)^4(5/6)^3 which is what you have.

another is SFSFSFS which would also be (1/6)^4(5/6)^3

in other words we have to count the number of arrangements of SSSSFFF which is C(7,4) or 35

So the prob of Tom's event is 35(1/6)^4(5/6)^3 or 4375/279936

which was Tom's answer.

So Tom was correct.

- Probability. -
**Anonymous**, Tuesday, October 18, 2011 at 9:54pm
.40

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