Posted by Tom on Thursday, May 22, 2008 at 12:16am.
Since a die is tossed seven times, for a), we want 4 comes up four times and a number other 4 three times. So,
(1/6)^4(5/6)^3
I think you can do the rest now.
not that simple
suppose we call getting a 4 is success (S) and not getting a 4 if failure (F)
one possibilty is SSSSFFF
The probability of that is (1/6)^4(5/6)^3 which is what you have.
another is SFSFSFS which would also be (1/6)^4(5/6)^3
in other words we have to count the number of arrangements of SSSSFFF which is C(7,4) or 35
So the prob of Tom's event is 35(1/6)^4(5/6)^3 or 4375/279936
which was Tom's answer.
So Tom was correct.
.40
Related Questions
Test tomm. Need help *Urgent* - Sorry for posting so many topics, but I really ...
English - Writeacher, I left out these sentences on the same topics. I included ...
PROBABILITY - The list of 16 topics was given to students to prepare for exam. ...
Math - Losing your bags during airline travel is not all that uncommon. Recently...
health - What is an example of a patient in crisis? A. A patient who is happily ...
biology - any type'a study to work on this stuff? I just need to memorize it...
science - i have a project for school and i need to seperate these things using ...
TEST TOMM. NEED HELP IMMEDIATELY. PROBABILITY - A fair coin is tossed ten times ...
math - You randomly draw letter tiles from a bag containing the letters from the...
Physics - Another one, sorry! =P This stuff is really confusing.. Why doesn'...
For Further Reading