A Jet airplane leaves an airport traveling at a steady rate of 600km/h. another jet leaves the same airport 3/4h later traveling at 800km/h in the same derection. how long will the 2nd jet take to overtake the first?

The equations for the distance travlled by the two planes are

X1 = 600 (t + 0.75) and
X2 = 800 t
where t is the time after the second plane leaves.

Set X1 = X2 to find the time t when Jet 2 overtakes Jet 1

800 t = 600 t + 450
200 t = 450
t = ? hours

i don't really get what you just said

What part don't you understand?

X1 is the distance travelled by the first car to leave. X2 is the distance travlled by the second car to leave.

I left you the last step to solve.

t = 450/200 = 2.25 hours is the answer

Omg im doung this exact problem in my math hw rn😂

To find out how long it will take for the second jet to overtake the first jet, we need to calculate the time it takes for them to cover the same distance.

Let's say the time taken by the second jet to overtake the first jet is 't' hours.

In the time taken by the second jet to overtake the first jet, the first jet has already been flying for 3/4 hour longer. So, the first jet would have covered a distance of (600 km/h) x (3/4 h) = 450 km.

Now, both jets are traveling at the same speed. So, we can set up the equation based on their relative speed:

Relative speed = speed of the second jet - speed of the first jet
Relative speed = 800 km/h - 600 km/h = 200 km/h

The distance the second jet needs to cover to overtake the first jet is 450 km.

We can use the formula: Distance = Speed x Time to find the time it takes for the second jet to cover 450 km at a speed of 200 km/h:

450 km = 200 km/h x t
t = 450 km / 200 km/h
t = 2.25 hours

Therefore, it will take the second jet 2.25 hours (or 2 hours and 15 minutes) to overtake the first jet.