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November 27, 2014

November 27, 2014

Posted by **ronny** on Wednesday, May 21, 2008 at 5:51am.

- physics -
**drwls**, Wednesday, May 21, 2008 at 6:41amThe fraction (1/6) that remains after 70 years satisfies the relation:

1/6 = 2^(-t/T),

where T is the half life and t = 70 years.

Take logs of both sides to solve for T. I'll use logs to base e but it doesn't matter

-1.7918 = -70/T ln 2 = -48.52/T

T = 27.1 years

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