Calculus
posted by Alex .
Let f(x) = sqrt(3x+15)
Find f'(x)
The answer is 3/(2sqrt(3x+15)
Can anyone who does this please explain step by step why you did what you did? I have a lot of difficulty finding the derivative with radicals.

Instead of radical form, write the problem in exponential form.
f(x)=(3x + 15)^(1/2)
f'(x)=(1/2)((3x+15)^(1/2  1)) 3
f'(x)=(3/2)(3x+15)^(1/2)
f'(x)=3/(2*(3x+15)^(1/2))