Please help! This is due tomorrow...
I don't understand how "Counting Outcomes and Theoretical Probability" works! There's a question that says:
You toss two coins. Find P (one head and one tail).
Please help!
The possible outcomes are:
H H
H T
T H
T T
The first number represents the first coin and the second number represents the second coin
There are two 1 head - 1 tail possibilities out of four possible outomes.
P = 2/4 = 1/2
thank you!
Sure! I can help you with that problem.
To find the probability of getting one head and one tail when tossing two coins, we need to first determine the total number of possible outcomes and then count the number of favorable outcomes.
Step 1: Determine the total number of possible outcomes
When tossing two coins, each coin can land either heads (H) or tails (T). Since there are two possible outcomes for each coin, the total number of possible outcomes when tossing two coins is calculated by multiplying the number of possibilities for each coin together:
Total number of possible outcomes = number of possibilities for coin 1 * number of possibilities for coin 2
= 2 * 2
= 4
So, there are 4 possible outcomes when tossing two coins.
Step 2: Count the number of favorable outcomes
Now, we need to count the number of outcomes that result in one head and one tail. We can list all the possible outcomes:
HT (head on the first coin, tail on the second coin)
TH (tail on the first coin, head on the second coin)
So, there are 2 favorable outcomes that result in one head and one tail.
Step 3: Calculate the probability
Finally, we can calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes:
P(one head and one tail) = number of favorable outcomes / total number of possible outcomes
= 2 / 4
= 1/2
= 0.5
Therefore, the probability of getting one head and one tail when tossing two coins is 0.5 or 1/2.
Sure, I'd be happy to explain how to solve this problem!
To find the probability of getting one head and one tail when tossing two coins, we first need to count the number of possible outcomes of the coin toss.
When you toss a coin, there are two possible outcomes: heads or tails. Since we are tossing two coins, we need to find the total number of outcomes. Each coin has two possibilities, so we can use the multiplication rule to determine the total number of outcomes:
Total number of outcomes = Number of outcomes for coin 1 * Number of outcomes for coin 2
In this case, it would be 2 * 2 = 4. So, there are four possible outcomes: HH (two heads), HT (one head and one tail), TH (one head and one tail), and TT (two tails).
Next, we need to find the number of outcomes that have one head and one tail. From the four possible outcomes we mentioned earlier, there are two outcomes that satisfy this condition: HT and TH.
Now that we have the number of favorable outcomes and the total number of possible outcomes, we can calculate the probability. The probability of an event happening is given by:
Probability = Number of favorable outcomes / Total number of possible outcomes
In this case, the number of favorable outcomes is 2, and the total number of possible outcomes is 4. So, the probability of getting one head and one tail when tossing two coins is:
Probability = 2/4 = 1/2 = 0.5
Therefore, the probability is 0.5 or 50%.
I hope this explanation helps you understand how to find the probability for this type of problem! If you have any further questions, feel free to ask.