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September 22, 2014

September 22, 2014

Posted by **Miley** on Monday, May 19, 2008 at 7:32pm.

3lnxy-2ln2y. whenever i condense i get ln(xy^3/2y2).

but my teacher has ln(x^3y/4).

can someone please show me how to get that answer thanks!

- alg 2. -
**Reiny**, Monday, May 19, 2008 at 7:49pm3lnxy-2ln2y

= ln(x^3y^3) - ln(4y^2

= ln [(x^3y^3)/(4y^2)]

= ln [(x^3y)/4]

- alg 2. -
**Miley**, Monday, May 19, 2008 at 7:57pmahhhaaa....thanks:)

- alg 2. -

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