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December 17, 2014

December 17, 2014

Posted by **jerson** on Monday, May 19, 2008 at 6:32pm.

- trig -
**Damon**, Monday, May 19, 2008 at 6:43pmin an isosceles right triangle the angles are 45,45,90

if the two legs have length x, then the hypotenuse has length sqrt(x^2+x^2) = x sqrt 2

so

tan 45 = x/x = 1

cot 45 = 1/tan 45 = 1/1 = 1

sin 45 = x /xsqrt 2 = sqrt 2/2

cos 45 =sqrt 2/2

sec 45 = 1/cos 45 = sqrt 2

csc 45 =1/sin 45 = sqrt 2

- trig -
**jerson**, Monday, May 19, 2008 at 6:46pmim confused with what you did. my teacher said it was something like

Co + 45°=1/tan45°

=1/O/A= A/O=1/1=1

- trig -
- trig -
**Damon**, Monday, May 19, 2008 at 6:52pmyes, that is what I said. Cot 45 = 1/tan 45 = 1

I also did the other trig functions of 45 because I am sure you will need them.

- trig -
**Anonymous**, Thursday, December 20, 2012 at 9:19amfind the value exact of cot 45.If the expression is underfined

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