Posted by jerson on Monday, May 19, 2008 at 6:32pm.
in an isosceles right triangle the angles are 45,45,90
if the two legs have length x, then the hypotenuse has length sqrt(x^2+x^2) = x sqrt 2
so
tan 45 = x/x = 1
cot 45 = 1/tan 45 = 1/1 = 1
sin 45 = x /xsqrt 2 = sqrt 2/2
cos 45 =sqrt 2/2
sec 45 = 1/cos 45 = sqrt 2
csc 45 =1/sin 45 = sqrt 2
im confused with what you did. my teacher said it was something like
Co + 45°=1/tan45°
=1/O/A= A/O=1/1=1
yes, that is what I said. Cot 45 = 1/tan 45 = 1
I also did the other trig functions of 45 because I am sure you will need them.
find the value exact of cot 45.If the expression is underfined
find the value exact of cot 45.If the expression is underfined
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