Thursday

December 18, 2014

December 18, 2014

Posted by **Anonymous** on Monday, May 19, 2008 at 2:50pm.

P(1)=1/3

P(2)=P(3)=P(4)=P(5)=P(6)

- probability -
**economyst**, Tuesday, May 20, 2008 at 10:58amI presume you gave the probability of the biased die, where there is a 33.33% chance of rolling a 1 and a 13.33% chance of rolling a 2,3,4,5 or 6. For a normal die, the probability of rolling any given number is 1/6 = 16.67%.

There is one way to roll a 2, both dies are 1. so, Psum(2) = .1666 * .3333 = .0555

There are two ways to roll an 3, 1-2, and 2-1. So Psum(3) = (.16666*.3333)+(.16666*.13333) = .0777

Repeat for values 4 to 12.

**Answer this Question**

**Related Questions**

math - a pair of dice are rolled and the sum on their upturned faces is recorded...

Statistics - A die that is fair will have each face of the die come up one-sixth...

Probability - Roll two fair dice. what is the probability that you get a 2 and a...

probability - Two six-sided dice each have the numbers 1 through 6 on their ...

probability - We have two fair three-sided dice, indexed by i=1,2. Each die has ...

Math-Probability - Please explain how to get the answer.I have now idea. 1.If ...

probability/statistics - You roll two fair dice, a white one and a red one. a. ...

probability - Consider n independent rolls of a k-sided fair die with k≥2...

Statistics - Find the probability that the sum is as stated when a pair of dice ...

statistics - A fair die is tossed and the number facing up is noted. If the ...