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March 2, 2015

March 2, 2015

Posted by **Oli** on Monday, May 19, 2008 at 8:57am.

Caluculate the temperature and pressure of the helium gas. (helium atom 4.0 amu)

How do I calculate the mass of helium? I got 2.0 x 10^-2 kg from (sample size/avogrado's constant) x 4.0 x 10^-3 kg.

Is this correct as when I put it into

T = (v^2 x m)/2k

I get a huge temp in the 8^30 K region which cannot be right!

What am I doing wrong here?

When I get the temp I can get the pressure from the ideal gas equation.

- Physics -
**drwls**, Monday, May 19, 2008 at 9:58amYou can get the temperature from the velocity distribution curve. The average kinetic energy is (1/2) m V^2 = (3/2) k T

where V^2 is the average V^2 of the atoms.

This tells you that the average V^2 is

V^2 = 3 k T/m, so

T = mV^2/(3 k)

k is the Boltzmann constant 1.3804*10^-23 Joule/K

m is the mass of a helium atom, which is 4.0 g/6.023*10^23 = 6.64*10^-27 kg.

The peak of the velocity distribution is not the same as the square root of the averge V^2, but is is pretty close. You can worry about the difference later. Using sqrt(Vpeak^2) for average V^2, I get

T = 6.64*10^-27 kg*(1100^2)m^2/s^2/3*(1.38*10^-23)J/K = 194 K

Now that you know T and the number density n (atoms/m^3), the equation

P = n k T

can be used for the pressure.

k is Boltzmann's constant. You could also use P = N R T, where R is the gas constant and N is the number of MOLES per m^3 and r is the gas constant.

Now for a fine point. In the Maxwellian velocity distribution of atoms, which is what you have, the peak velocity Vp differs from Vrms.

Vp = sqrt(2/3)* Vrms = 0.816 Vrms

See http://hyperphysics.phy-astr.gsu.edu/Hbase/kinetic/kintem.html

for an explanation.

To get the temperature, I should have used Vp instead of Vrms. This has the effect of lowering the temperature by a factor 2/3.

- Physics -
**Oli**, Monday, May 19, 2008 at 4:26pmThanks for the help drwls.

I have now also found the average kinectic energy of the helium atoms.

But what is the position of the maximum in the energy distribution? Is this the peak energy that I need to find?

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