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April 18, 2015

April 18, 2015

Posted by **sam** on Sunday, May 18, 2008 at 11:15pm.

a) at the instant when the radius of oil slick is 100 cenimetters and the hieght is 0.5 cm the radius is increasing at the rate of 2.5 cm per min. at this instant what is the rate of change of the height of oil slick with respect to time in cm per min

- calculus -
**Reiny**, Monday, May 19, 2008 at 12:56amlet the thickness of the oil slick be h cm

let the radius be r cm

let the volume be V cm^3

given:

dV/dt = 2000cm^3/min

when r=100 cm, dr/dt = 2.5 cm/min and

V=pi(r^2)h

dV/dt = pi(r^2)dh/dt + 2pi(r)(h)dr/dt

2000 = pi)100^2)dh/dt + 2pi(100)(.5)(2.5)

solve for dh/dt

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