Posted by Alex on Sunday, May 18, 2008 at 4:28pm.
2) A 3kg ball moving east strikes a 2kg ball that is moving east at 2m/s. Following the collision the 3kg ball moves at 4m/s in a direction [E55S] while the other ball moves in a direction of [E35N].
a) By considering components of momentum in a N-S direction, calculate the speed that the 2kg ball had after the collision.
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a)
Initial momentum N is zero
final momentum N:
0 = 2 (s sin 35) - 3 (4 sin 55)
s = 12 sin 55 / 2 sin 35 = 9.83/1.15
s = 8.55 m/s
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b) By considering conservation of momentum in an east-west direction, find the initial speed of the 3kg ball.
--------------------------------
initial momentum E = 3 v + 2*2 = 4 + 3 v
final momentum E = 2*8.55 cos35 + 3*4 cos 55
so
4+3v = 14+6.88
3 v = 16.88
v = 5.63
What about the answer to #3?
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