Posted by **Tareena-- can some one check my answer please** on Sunday, May 18, 2008 at 12:17pm.

From a hand glider approaching a 6000 foot clearing the angles of depression of the opposite ends of the field measure 24 degrees and 30 degrees. how far is the hang glider from the nearer end of the field?

Math - drwls, Saturday, May 17, 2008 at 11:40pm

The third angle of the triangle formed by the hang glider and the two edges of the field is 180 - 24 - 30 = 126 degrees. This is the angle subtended by the field. The side opposite that subtended angle has a length of 6000 ft (the clearing length). Use the law of sines for the other two triangle sides. The side opposite the 24 dsegree corner will be the distance to the nearest edge.

Tareena:

Suppose

A=30

B=24

C=126

sin A= sin30 x 6000/sin 126=3708

sin B= sin24 x 6000/sin 126=6148

- Math -
**drwls**, Sunday, May 18, 2008 at 3:24pm
My mistake. The closest edge has the largest angle of depression.

Your method is correct, but you are solving for sides a and b, not the angles A and B .

a = 3708 m is the answer.

- Math -
**Damon**, Sunday, May 18, 2008 at 3:32pm
I think the angles of the triangle are:

24

180-30 = 150

180 - 24 - 150 = 30 - 24 = 6

so I think

sin 24 / x = sin 6/6000

x = 6000 (sin 24 /sin 6)

= 6000 (.407/.105) = 23,257

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