Posted by **doug** on Sunday, May 18, 2008 at 2:44am.

determine vertex, focus and directrix of parabola. then graph the parabola.

first equation:

y^2 -2x-8=0

second equation:

y^2 -4y -12x= 8

- math -
**drwls**, Sunday, May 18, 2008 at 8:32am
We can't draw graphs for you here. I sugggest you do that yourself

Rewrite them in the form

x = a(y-b)^2 + c

When you have done that, the vertex will be at x=c, y=b. The focus will be located at y=b, x = c + p, and the directrix will be the line x = c - p

The value of p is

p = 1/(4a)

For your first equation,

x = y^2/2 -4

so a = 1/2, b = 0 and c = -4

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