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November 28, 2014

November 28, 2014

Posted by **Tamana** on Saturday, May 17, 2008 at 12:29pm.

- Math -
**drwls**, Saturday, May 17, 2008 at 12:39pmYou can use the law of sines here, on a triangle formed by the ship and the two docks.

(sin 35)/10 = sin B/8

Use that to solve for sin B, which is the angle opposite the 8 km side of the triangle. Then solve for third angle C using

C = 180 - 35 - B

Finally, use

sin A/10 = sin C/c

c is the side length that you want.

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