Posted by Tamana on Saturday, May 17, 2008 at 12:29pm.
The captain of a freighter 8 km from the nearer of two unlaoding docks on the shore finds that the angle between the lines of sight to the two docks is 35 degrees. if the docks are 10km apart, how far is the tanker from the farther dock?

Math  drwls, Saturday, May 17, 2008 at 12:39pm
You can use the law of sines here, on a triangle formed by the ship and the two docks.
(sin 35)/10 = sin B/8
Use that to solve for sin B, which is the angle opposite the 8 km side of the triangle. Then solve for third angle C using
C = 180  35  B
Finally, use
sin A/10 = sin C/c
c is the side length that you want.
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