Saturday

August 30, 2014

August 30, 2014

Posted by **Tamana** on Saturday, May 17, 2008 at 12:29pm.

- Math -
**drwls**, Saturday, May 17, 2008 at 12:39pmYou can use the law of sines here, on a triangle formed by the ship and the two docks.

(sin 35)/10 = sin B/8

Use that to solve for sin B, which is the angle opposite the 8 km side of the triangle. Then solve for third angle C using

C = 180 - 35 - B

Finally, use

sin A/10 = sin C/c

c is the side length that you want.

**Related Questions**

MATH - The Captain of a freighter 8km fromthe nearer of two unloading docks on ...

Math - The Captain of a freighter 8km fromthe nearer of two unloading docks on ...

Math - The Captain of a freighter 8km fromthe nearer of two unloading docks on ...

math - The CN Tower in Toronto, Canada, is the tallest free-standing structure ...

Math - The CN Tower in Toronto, Canada, is the tallest free-standing structure ...

Geometry - The distance between two docks on opposite sides of a river is 90 ...

trigonometry - From a mountain 1780 ft. high, the angle of depression of a point...

math - From a mountain 1780 ft. high, the angle of depression of a point on the ...

Geometry - If two non parallel lines are perpendicular to two other straight ...

physics - Somewhere between the Earth and the Moon, the gravitational pull ...