Thursday
March 23, 2017

Post a New Question

Posted by on Saturday, May 17, 2008 at 9:34am.

find the dy/dx for:

y^2=(2x^3)y+5x

  • implicit differentiation - , Saturday, May 17, 2008 at 10:42am

    With y considered a function of x, differentiate both sides of the equation with respect to x. Then solve for dy/dx.

    2y dy/dx = (2x^3) dy/dx + y*(6x^2)+ 5

    dy/dx(2y-2x^3) = 6x^2*y +5
    dy/dx = [6x^2*y+5)/(2y-2x^3)

  • implicit differentiation - , Saturday, May 17, 2008 at 10:45am

    2y(dy/dx) = 2x^3(dy/dx) + (6x^2)y + 5
    2y(dy/dx) - 2x^3(dy/dx) = (6x^2)y + 5

    dy/dx(2y - 2x^3) = 6x^2y + 5

    dy/dx = ((6x^2)y + 5)/(2y - 2x^3)

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question