Last week i did a lab and i just wanted to show you my results because my computer was acting weird when i used the voltage probe.(I just needed you to check that the cathode and anodes and voltages make sense)

CuSO4(cathode)and Al2(SO4)3 (anode)--[0.050V]

cuSO4(anode) and ZnSO4(cathode)-- [0.048 V]

MgSO4(anode)and ZnSO4(cathode)--[0.284 V]

ZnSO4(anode) and AlSO4(cathode)-- [-0.056V]

Al2(SO4)3(cathode) and MgSO4(anode)--[0.966 V]

CuSO4(cathode)and ZnSO4(anode)--[-0.484]

I can't check any of the voltages; I assume these were at other than 1 M. For the Al/Cu (#1 below) the voltage would be about 2.0 volts for 1 M solutions of each. Also, it MIGHT be possible, for some that I have suggested as the other way around below, could be correct if the concentrations were not 1 M.


CuSO4(cathode)and Al2(SO4)3 (anode)--[0.050V]
OK.

cuSO4(anode) and ZnSO4(cathode)-- [0.048 V]
I think Zn is the anode and Cu is the cathode.

MgSO4(anode)and ZnSO4(cathode)--[0.284 V]
OK\

ZnSO4(anode) and AlSO4(cathode)-- [-0.056V]
I think Al is the anode and Zn is the cathode.

Al2(SO4)3(cathode) and MgSO4(anode)--[0.966 V]
OK

CuSO4(cathode)and ZnSO4(anode)--[-0.484]
OK

They are 0.1 M solutions. I have tons of post lab dicussion questions you think you can help me with them? I don't even know where to start

I suppose what you posted above are some of the tons of discussion questions. I think I answered one of them completely enough that you can follow that for the others.

Dear sir

Good morning Sir we run a Company SENDHOOR CHEMICAS and we supply mag

Sure! I can help you check if the cathode, anode, and voltages make sense in your lab results.

In electrochemistry, a redox reaction occurs where there is a transfer of electrons from the reducing agent (the species being oxidized) to the oxidizing agent (the species being reduced). The cathode is where reduction occurs, while the anode is where oxidation occurs.

Let's start with the first set of your results:
CuSO4 (cathode) and Al2(SO4)3 (anode) - [0.050V]
This means that copper(II) sulfate is reduced at the cathode, while aluminum sulfate is oxidized at the anode. The voltage reading of 0.050V indicates the potential difference between the two half-reactions.

Next, we have:
CuSO4 (anode) and ZnSO4 (cathode) - [0.048V]
This reaction shows copper(II) sulfate being oxidized at the anode and zinc sulfate being reduced at the cathode, with a voltage reading of 0.048V.

Moving on to the next set:
MgSO4 (anode) and ZnSO4 (cathode) - [0.284V]
This reaction involves magnesium sulfate being oxidized at the anode and zinc sulfate being reduced at the cathode, with a voltage reading of 0.284V.

Now, we have:
ZnSO4 (anode) and AlSO4 (cathode) - [-0.056V]
In this case, zinc sulfate is being oxidized at the anode, and aluminum sulfate is being reduced at the cathode. The negative voltage reading (-0.056V) may indicate a reverse reaction or an error in measurement.

Moving to the next one:
Al2(SO4)3 (cathode) and MgSO4 (anode) - [0.966V]
Here, aluminum sulfate is reduced at the cathode, while magnesium sulfate is oxidized at the anode, with a voltage reading of 0.966V.

Finally, we have:
CuSO4 (cathode) and ZnSO4 (anode) - [-0.484V]
Copper(II) sulfate is being reduced at the cathode, and zinc sulfate is being oxidized at the anode, with a voltage reading of -0.484V. Again, the negative value indicates a reverse reaction or a potential error in measurement.

Overall, most of the cathode/anode combinations and voltage readings in your lab results align with the expected redox reactions. However, the negative voltage readings in the last two cases suggest there might be some errors or anomalies in your experiment.

It's important to note that the voltage values you obtained may vary depending on factors like concentration, temperature, and electrode materials. To ensure accurate and consistent results, it's essential to carefully perform the experiment, use reliable electrodes, and calibrate the equipment properly.

I hope this explanation helps you understand your lab results! If you have any further questions, feel free to ask.