Posted by Pam on Friday, May 16, 2008 at 10:09am.
Can someone please tell me how to solve this problem? Trying to help a teen who is staying with me with their homework, but I am clueless.
Thanks.

Algebra  bobpursley, Friday, May 16, 2008 at 10:17am
Please post the question.

Algebra  Pam, Friday, May 16, 2008 at 10:33am
Oops....sorry, I forgot to put the problem in.
2y = 228 + 8x
10x + 11y = 64
Solve each system of equations using the substitution method.

Algebra  bobpursley, Friday, May 16, 2008 at 1:41pm
Put them in standard form:
8x+2y=228
10x+11y=64
Elminate a variable. I will pick x. Multiply the top equation by 10, the second equation by 8
80x+20y=2280
80x+88y=64*8
now subtract the second equation from the first..
68y=2280+64*8
and proceed to solve for y. Then, substitue back in the original equation, either one, and solve for x.

Algebra  anthony, Friday, May 16, 2008 at 2:54pm
x+y=8 3xy=4
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