Monday
July 28, 2014

Homework Help: Electrochemistry

Posted by Donna on Friday, May 16, 2008 at 1:30am.

Qualitively explain the effect of changing concentration of Cu^2+ using your experimental observations and the Keq values below (no calculations required)

Cu^2+(aq) + 4 NH3(aq) --> [Cu(NH3)4]^2+(aq) , Keq = 1.2x10^12
CuS(s) --> Cu^2+(aq) + S^2-(aq) , Keq = 8.5 x 10^-45

Cu/Zn = 0.525 V
after 1 drop NH3: 0.505 V
after 2 drops NH3: 0.435 V

Cu/Zn = 0.510 V
after 1 drop Na2S: 0.452 V
after 2 drops Na2S: 0.393 V

So I know Voltage obviously decreases with added concentration, but how does the Keq account for that?

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