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November 24, 2014

November 24, 2014

Posted by **Megan** on Thursday, May 15, 2008 at 9:11pm.

- Math -
**drwls**, Friday, May 16, 2008 at 6:20amLet y be the height. The diameter D must satisfy

(pi/4) D^2 y = 3*10^5 ft^3

The area to be painted (including the top) is

A = pi [D^2/4 + D y]

Substitute using the first equation to eliminate y.

A = pi [D^2/4 + 3*10^5 (4/pi)(1/D)]

Set dA/dD = 0 and solve for D

D/2 - (12*10^5/pi)/D^2 = 0

D^3 = 24*10^5/pi

D = 92.6 ft

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