Posted by **sam** on Thursday, May 15, 2008 at 7:58pm.

find the eq to the tangent line to the curve y=x^3 g(x) at x=1 if g(1)=2 f(1)=3 f'(1)=1 g'(1)=-2

i cant understand how the answer is y=4x-2

- math urgent! -
**Reiny**, Thursday, May 15, 2008 at 8:07pm
you are probably not getting a response to your question since others along with me cannot figure out what you mean by

.... g(x) at x=1 if g(1)=2 f(1)=3 f'(1)=1 g'(1)=-2

if y = 4x-2 is the tangent equation then the contact point would have an x value of 2/√3, and I see no √3 anywhere.

you speak of g(x) and f(x) but state your equation y = x^3.

Quite confusing.

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