Posted by **sam** on Thursday, May 15, 2008 at 7:58pm.

find the eq to the tangent line to the curve y=x^3 g(x) at x=1 if g(1)=2 f(1)=3 f'(1)=1 g'(1)=-2

i cant understand how the answer is y=4x-2

- math urgent! -
**Reiny**, Thursday, May 15, 2008 at 8:07pm
you are probably not getting a response to your question since others along with me cannot figure out what you mean by

.... g(x) at x=1 if g(1)=2 f(1)=3 f'(1)=1 g'(1)=-2

if y = 4x-2 is the tangent equation then the contact point would have an x value of 2/√3, and I see no √3 anywhere.

you speak of g(x) and f(x) but state your equation y = x^3.

Quite confusing.

## Answer this Question

## Related Questions

- math - find the eq to the tangent line to the curve y=x^3 g(x) at x=1 if g(1)=2 ...
- Calculus - If F(x)=x^3−7x+5, use the limit definition of the derivative to...
- calculus - Consider line segments which are tangent to a point on the right half...
- Help Calc.! - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+y^2+1...
- please help; calc - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+...
- Calculus - Please help this is due tomorrow and I dont know how to Ive missed a ...
- calculus - Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 . a. Show ...
- Need help fast on calc - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy...
- Calculus - Suppose that y=f(x) = sqrt(2x), x>=0 Find a c > 0 such that the...
- 12th Grade Calculus - 1. a.) Find an equation for the line perpendicular to the ...