Friday

September 19, 2014

September 19, 2014

Posted by **Samantha** on Thursday, May 15, 2008 at 7:50pm.

14>(10)(sin 40)

And this means that there are two solutions according to the equations my teacher gave me.

What do I do now?

- Algebra II -
**Reiny**, Thursday, May 15, 2008 at 8:02pmby Sine Law :

sinB/b = sinA/a

sinB/10 = sin40/14

sinB = .459134

angle B = 27.33º or 180-27.33º

so B is either 27.33 or 152.67º

draw the two possible triangles, and use the sine law again to find c.

- Algebra II -
**Samantha**, Thursday, May 15, 2008 at 8:07pmOh, I see. So there would be two solutions for both B and C. I would just solve it like a regular triangle, and B' and C' would be 180 minus the values of B and C. Thanks!

- Algebra II -
**Reiny**, Thursday, May 15, 2008 at 8:18pmYou got it !!

- Algebra II -

**Answer this Question**

**Related Questions**

TRig WIth LoGs help1!! - i have problem i can't solve and the book is no help.. ...

algebra - Can someone please help me do this problem? That would be great! ...

Math - 1. Find the value of Sin^-1(-1/2) a. -30 degrees b. 30 degrees c. 150 ...

math - 1)In triangle ABC, C=60 degrees, a=12, and b=5. Find c. A)109.0 B)10.4 C)...

math - find all solutions in the interval [0,2 pi) sin(x+(3.14/3) + sin(x- 3.14/...

HELP! math........quick will only take like 2 min. - What two sides of a right ...

Math - Use the given information to solve the triangle. If two solutions exists...

Math - Use the given information to solve the triangle. If two solutions exists...

Math - Use the given information to solve the triangle. If two solutions exists...

Trigonometry - Solve the equation cos^2A = sin^2A + sinA when 0¨¬¡ÂA¡Â360¨¬. ...