Posted by **sam** on Thursday, May 15, 2008 at 7:26pm.

find the eq to the tangent line to the curve y=x^3 g(x) at x=1 if g(1)=2 f(1)=3 f'(1)=1 g'(1)=-2

i cant understand how the answer is y=4x-2

## Answer this Question

## Related Questions

math urgent! - find the eq to the tangent line to the curve y=x^3 g(x) at x=1 if...

Calculus - If F(x)=x^3−7x+5, use the limit definition of the derivative to...

calculus - Consider line segments which are tangent to a point on the right half...

Help Calc.! - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+y^2+1...

please help; calc - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+...

Calculus - Please help this is due tomorrow and I dont know how to Ive missed a ...

calculus - Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 . a. Show ...

Need help fast on calc - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy...

12th Grade Calculus - 1. a.) Find an equation for the line perpendicular to the ...

Calculus - the curve: (x)(y^2)-(x^3)(y)=6 (dy/dx)=(3(x^2)y-(y^2))/(2xy-(x^3)) a...