please can someone help me with this problem. I am doing substitution.

3x + 4y = 0
y = x you have to substituted the y for x

Then the same other problem with different number.
y = x
-6x + 8y = -2

since y = x

in the first equation
3x + 4y = 0
3x + 4(x) = 0
7x = 0
x = 0 , since y=x, y = 0

do the same thing in the second problem.

Thank you Reiny you really help me.

Of course! I can help you with these substitution problems.

Let's start with the first problem:
1. We have the equation 3x + 4y = 0 and the equation y = x.
2. To substitute y for x in the first equation, replace every occurrence of y with x.
So, the first equation becomes: 3x + 4(x) = 0.
3. Simplify the equation: 3x + 4x = 0.
4. Combine like terms: 7x = 0.
5. Divide both sides of the equation by 7 to solve for x: x = 0.
6. Since y = x, we substitute x = 0 back into the equation y = x.
Therefore, y = 0.

So the solution to the first problem is x = 0 and y = 0.

Now let's move on to the second problem:
1. We have the equation y = x and the equation -6x + 8y = -2.
2. Since y = x, we can substitute x for y in the second equation.
So, the second equation becomes: -6x + 8(x) = -2.
3. Simplify the equation: -6x + 8x = -2.
4. Combine like terms: 2x = -2.
5. Divide both sides of the equation by 2 to solve for x: x = -1.
6. Since y = x, we substitute x = -1 back into the equation y = x.
Therefore, y = -1.

So the solution to the second problem is x = -1 and y = -1.

I hope this helps! Let me know if you have any further questions.