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March 28, 2017

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Need help on factoring. HOw exactly would I solve these(big test coming up):

-3x to the second+18x+12

-5x to the second-13x=6

-5x to the second-6x=1

-and xto the second + 6x=10

I can't use the quadratic equation. I have to use the a times c method.

  • RE: Math - ,

    Two things:
    1. I think your first equation has a typo, since it is not an equation

    2. I think you are using the - in front of each equation not as a negative sign, but rather as a dash. Why????

    So I will assume that your second equation is

    5x^2 - 13x = 6 (the ^ means 'to the exponent')

    5x^2 - 13x - 6 = 0

    (a)(c) = 5(-6) = -30

    now look for factors of -30 which have a sum of -13

    that would be -15 and 2
    check :(-15)(2) = -30, -15 + 2 = -13

    now replace the middle term of -13x with -15x+2x

    5x^2 - 15x + 2x - 6 = 0

    take out a common factor from the first two terms, and from the last two terms

    5x(x-3) + 2(x-3) = 0
    now x-3 is a common factor, so ...
    (x-3)(5x+2) = 0
    x-3 = 0 or 5x+2 = 0
    x = 3 or x = -2/5

  • RE: Math - ,

    Do the others the same way

  • RE: Math - ,

    So You using the quadratic or a time c method will give me the same answer?

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