x11 + 15y = 58
The equation you provided is a linear equation with two variables, x and y. To solve for the values of x and y that satisfy this equation, we can use various methods such as substitution or elimination.
To solve this equation, we can use the elimination method. The goal is to eliminate one of the variables by multiplying the equations with suitable coefficients so that the coefficients of one variable will cancel each other out when the equations are added or subtracted.
Given equation:
x11 + 15y = 58 ---(1)
To eliminate the variable x, we need to multiply equation (1) by a constant such that when added to or subtracted from the other equation, the x term cancels out.
To do this, we can multiply equation (1) by 11, resulting in:
11(x11 + 15y) = 11(58)
11x + 165y = 638 ---(2)
Now we have two equations:
11x + 165y = 638 ---(2)
x11 + 15y = 58 ---(1)
We can now subtract equation (1) from equation (2) to eliminate x:
(11x + 165y) - (x11 + 15y) = 638 - 58
Simplifying the left side and the right side of the equation:
11x + 165y - x11 - 15y = 638 - 58
11x - x11 + 165y - 15y = 580
Combining like terms:
(11 - 1)x + (165 - 15)y = 580
10x + 150y = 580
Now we have a new equation:
10x + 150y = 580 ---(3)
Since the coefficients of both x and y in equation (3) are multiples of 10, we can simplify it by dividing both sides of the equation by 10:
(10x + 150y)/10 = 580/10
x + 15y = 58
Now we have a simplified equation (equation (1)) obtained by eliminating x:
x + 15y = 58
This equation can be used to express x in terms of y or y in terms of x. However, if you provide additional constraints or a second equation, we can find specific values for x and y that satisfy both equations.