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November 28, 2014

November 28, 2014

Posted by **Tyler** on Thursday, May 15, 2008 at 7:18am.

so would I take 5280 divided by 80 for a total of 66 then subtract 22 from the 66 and that's the width of the pool?

- Math -
**Reiny**, Thursday, May 15, 2008 at 7:49amlet the length and width be represented by l and w

"80 times the length equals 1 mile" --->

80l=5280

l = 5280/80 = 66

so your first part was right.

perimeter = 2l + 2w

22(2l+2w) = 5280

2l + 2w = 240

l + w = 120, but l=66

66+w = 120

w = 54

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