Tuesday

September 2, 2014

September 2, 2014

Posted by **Tyler** on Thursday, May 15, 2008 at 7:18am.

so would I take 5280 divided by 80 for a total of 66 then subtract 22 from the 66 and that's the width of the pool?

- Math -
**Reiny**, Thursday, May 15, 2008 at 7:49amlet the length and width be represented by l and w

"80 times the length equals 1 mile" --->

80l=5280

l = 5280/80 = 66

so your first part was right.

perimeter = 2l + 2w

22(2l+2w) = 5280

2l + 2w = 240

l + w = 120, but l=66

66+w = 120

w = 54

**Answer this Question**

**Related Questions**

Math - Freshman math question, super confused! Today while Don was swimming, he ...

Algebra - HELP!!! Super confused. Here's the problem. Today while Don was ...

math - mr. ming may swim the perimeter of Pool A or Pool B. In which pool must ...

math - mr. ming may swim the perimeter of Pool A or Pool B. In which pool must ...

English - Can you swim? 1. Yes, I can swim very well. 2. Yes, I can swim a ...

Math - My cousin Robert was pushed into a pool. The pool was 6 feet Wide and 10 ...

Math;Pre-Algebra - My cousin Robert was pushed into a pool. The pool was 6 feet ...

Math - A swimming pool is 50 meters long. If I swim 60 lengths of the pool each ...

algebra - keisha told her swim coach that she would swim at least half a mile. ...

Geometry. - A park has a circular swimming pool. The diameter of the pool is 18 ...