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July 28, 2014

July 28, 2014

Posted by **Mike** on Wednesday, May 14, 2008 at 9:55pm.

- pre-calculus -
**Reiny**, Wednesday, May 14, 2008 at 11:51pm3(4^x)-2^(x+2) = -1

3(2^2)^x - (2^x)(2^2) + 1 = 0

3(2^x)^2 - 4(2^x) + 1 = 0

let 2^x = m

3n^2 - 4m + 1 = 0

(3m - 1)(m - 1) = 0

m = 1/3 or m = 1

so 2^x = 1/3

x = ln(1/3)/ln2 = appr. -1.585

or

2^x = 1

x = 0

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