Posted by JOSHUA on Wednesday, May 14, 2008 at 9:47pm.
This looks like integral calculus, so why do they call it precalculus?
The area is the definite integral of the function y(x) from 3 to 6.
The definite integral is the change in the indefinite integral going from x=3 to x=6.
The indefinite integral is
(2/3)x^3 +x^2/2 + x
Calculate the value of that function at x=6 and subtract the value at x=3.
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