Wednesday

October 22, 2014

October 22, 2014

Posted by **jennifer** on Wednesday, May 14, 2008 at 9:42pm.

Evaluate

5

(x^3-2x)dx

2

- Calc or Pre calc -
**drwls**, Wednesday, May 14, 2008 at 10:27pmTo get the definite integral subtract the value of the indefinite integral at x=2 from the value at x=5. The arbitrary cnstant c will cancel out.

The indefinite integral is x^4/4 - x^2 + C.

The definite integral is

(625/4) - 25 -[16/4 - 4].

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