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April 20, 2014

April 20, 2014

Posted by **Elena** on Wednesday, May 14, 2008 at 9:31pm.

Evaluate the definite integral

4

x(x+3)dx

0

- Calculus -
**Reiny**, Wednesday, May 14, 2008 at 9:35pmexpand it first to get

⌠ (x^2 + 3x)dx from 0 to 4

⌡

= (x^3)/3 + (3/2)x from 0 to 4

= 64/3 + 6 - 0

= 82/3

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