Sunday
March 26, 2017

Post a New Question

Posted by on .

I got this problem today in school, and I don't know how to go about soving it. Can someone show me. Thanks. Here it is.

The distance s(t) between an object and its starting point is given by the antiderivative of velocity function v(t). Find the distance between the object and its starting point after 15 seconds if v(t)=0.4t^2+6 meters per second.
My teacher said that I wouldn't be able to solve it, so I really want some help with this thanks.

  • Math Help Please - ,

    since v(t) = s'(t), then

    s(t) = (.4t^3)/3 + 6t + c
    at the start (t=0) s(0) = c
    at t=15, s(15) = .4(3375)/3 + 6(15) + c

    so the distance traveled
    = .4(3375)/3 + 6(15) + c - c
    = 540

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question