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November 29, 2014

November 29, 2014

Posted by **Johnathan** on Wednesday, May 14, 2008 at 9:26pm.

The distance s(t) between an object and its starting point is given by the antiderivative of velocity function v(t). Find the distance between the object and its starting point after 15 seconds if v(t)=0.4t^2+6 meters per second.

My teacher said that I wouldn't be able to solve it, so I really want some help with this thanks.

- Math Help Please -
**Reiny**, Wednesday, May 14, 2008 at 9:32pmsince v(t) = s'(t), then

s(t) = (.4t^3)/3 + 6t + c

at the start (t=0) s(0) = c

at t=15, s(15) = .4(3375)/3 + 6(15) + c

so the distance traveled

= .4(3375)/3 + 6(15) + c - c

= 540

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