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October 21, 2014

October 21, 2014

Posted by **Neil** on Wednesday, May 14, 2008 at 9:13pm.

Find the sope of the tangent line to the graph of the equation

y=x^2(x-3) at x=-1

Thanks for the help.

- Mathmatics -
**Reiny**, Wednesday, May 14, 2008 at 9:19pmthe slope of the tangent line at a given point equals the value of the first derivative at that point, so ...

y' = 3x^2 - 6x

when x = -1

y' = 3 - (-6) = 9

(in your next lesson you will probably find the equation of that tangent)

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