Mathmatics
posted by Neil on .
I need help. I have no clue about how to solve this problem. Can someone go through it.
Find the sope of the tangent line to the graph of the equation
y=x^2(x3) at x=1
Thanks for the help.

the slope of the tangent line at a given point equals the value of the first derivative at that point, so ...
y' = 3x^2  6x
when x = 1
y' = 3  (6) = 9
(in your next lesson you will probably find the equation of that tangent)