posted by Josh on .
Can someone help me with this problem...I have no Idea how to do it.
Find the area between each curve and the x-axis for the given interval.
y=16x-x^3 from x=0 to x=4
Thanks for the help>>
A quick analysis and sketch of the curve will show x-intercepts at -4,0, and 4
Since you want the area from 0 to 4, it will be the region above the x-axis.
⌠ 16x - x^3 dx from 0 to 4
= [8x^2 - 1/4x^4] from 0 to 4
= (8(16) - 1/4(256)) - 0
I find your statement "..I have no Idea how to do it" rather puzzling. This is a routine and quite simple problem in this topic, if you are studying Calculus