Posted by **Josh** on Wednesday, May 14, 2008 at 8:46pm.

Can someone help me with this problem...I have no Idea how to do it.

Find the area between each curve and the x-axis for the given interval.

y=16x-x^3 from x=0 to x=4

Thanks for the help>>

- Pre Calculus -
**Reiny**, Wednesday, May 14, 2008 at 9:03pm
A quick analysis and sketch of the curve will show x-intercepts at -4,0, and 4

Since you want the area from 0 to 4, it will be the region above the x-axis.

area =

⌠ 16x - x^3 dx from 0 to 4

⌡

= [8x^2 - 1/4x^4] from 0 to 4

= (8(16) - 1/4(256)) - 0

= 128-64

= 64

I find your statement "..I have no Idea how to do it" rather puzzling. This is a routine and quite simple problem in this topic, if you are studying Calculus

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